y^3/2-8y^1/2+12y^-1/2=o

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Solution for y^3/2-8y^1/2+12y^-1/2=o equation: 


x in (-oo:+oo)

(y^3)/2-((8*y^1)/2)+(12*y^-1)/2 = o // - o

(y^3)/2-o-((8*y^1)/2)+(12*y^-1)/2 = 0

(y^3)/2-o-4*y+(12*y^-1)/2 = 0

1/2*y^3-o-4*y+6*y^-1 = 0

x naleu017Cy do R

x in (-oo:+oo)

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